Integrand size = 19, antiderivative size = 101 \[ \int \frac {1}{(a+b x)^{15/4} \sqrt [4]{c+d x}} \, dx=-\frac {4 (c+d x)^{3/4}}{11 (b c-a d) (a+b x)^{11/4}}+\frac {32 d (c+d x)^{3/4}}{77 (b c-a d)^2 (a+b x)^{7/4}}-\frac {128 d^2 (c+d x)^{3/4}}{231 (b c-a d)^3 (a+b x)^{3/4}} \]
[Out]
Time = 0.01 (sec) , antiderivative size = 101, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {47, 37} \[ \int \frac {1}{(a+b x)^{15/4} \sqrt [4]{c+d x}} \, dx=-\frac {128 d^2 (c+d x)^{3/4}}{231 (a+b x)^{3/4} (b c-a d)^3}+\frac {32 d (c+d x)^{3/4}}{77 (a+b x)^{7/4} (b c-a d)^2}-\frac {4 (c+d x)^{3/4}}{11 (a+b x)^{11/4} (b c-a d)} \]
[In]
[Out]
Rule 37
Rule 47
Rubi steps \begin{align*} \text {integral}& = -\frac {4 (c+d x)^{3/4}}{11 (b c-a d) (a+b x)^{11/4}}-\frac {(8 d) \int \frac {1}{(a+b x)^{11/4} \sqrt [4]{c+d x}} \, dx}{11 (b c-a d)} \\ & = -\frac {4 (c+d x)^{3/4}}{11 (b c-a d) (a+b x)^{11/4}}+\frac {32 d (c+d x)^{3/4}}{77 (b c-a d)^2 (a+b x)^{7/4}}+\frac {\left (32 d^2\right ) \int \frac {1}{(a+b x)^{7/4} \sqrt [4]{c+d x}} \, dx}{77 (b c-a d)^2} \\ & = -\frac {4 (c+d x)^{3/4}}{11 (b c-a d) (a+b x)^{11/4}}+\frac {32 d (c+d x)^{3/4}}{77 (b c-a d)^2 (a+b x)^{7/4}}-\frac {128 d^2 (c+d x)^{3/4}}{231 (b c-a d)^3 (a+b x)^{3/4}} \\ \end{align*}
Time = 0.36 (sec) , antiderivative size = 77, normalized size of antiderivative = 0.76 \[ \int \frac {1}{(a+b x)^{15/4} \sqrt [4]{c+d x}} \, dx=-\frac {4 (c+d x)^{3/4} \left (77 a^2 d^2+22 a b d (-3 c+4 d x)+b^2 \left (21 c^2-24 c d x+32 d^2 x^2\right )\right )}{231 (b c-a d)^3 (a+b x)^{11/4}} \]
[In]
[Out]
Time = 0.67 (sec) , antiderivative size = 105, normalized size of antiderivative = 1.04
method | result | size |
gosper | \(\frac {4 \left (d x +c \right )^{\frac {3}{4}} \left (32 d^{2} x^{2} b^{2}+88 x a b \,d^{2}-24 x \,b^{2} c d +77 a^{2} d^{2}-66 a b c d +21 b^{2} c^{2}\right )}{231 \left (b x +a \right )^{\frac {11}{4}} \left (a^{3} d^{3}-3 a^{2} b c \,d^{2}+3 a \,b^{2} c^{2} d -b^{3} c^{3}\right )}\) | \(105\) |
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 252 vs. \(2 (83) = 166\).
Time = 0.54 (sec) , antiderivative size = 252, normalized size of antiderivative = 2.50 \[ \int \frac {1}{(a+b x)^{15/4} \sqrt [4]{c+d x}} \, dx=-\frac {4 \, {\left (32 \, b^{2} d^{2} x^{2} + 21 \, b^{2} c^{2} - 66 \, a b c d + 77 \, a^{2} d^{2} - 8 \, {\left (3 \, b^{2} c d - 11 \, a b d^{2}\right )} x\right )} {\left (b x + a\right )}^{\frac {1}{4}} {\left (d x + c\right )}^{\frac {3}{4}}}{231 \, {\left (a^{3} b^{3} c^{3} - 3 \, a^{4} b^{2} c^{2} d + 3 \, a^{5} b c d^{2} - a^{6} d^{3} + {\left (b^{6} c^{3} - 3 \, a b^{5} c^{2} d + 3 \, a^{2} b^{4} c d^{2} - a^{3} b^{3} d^{3}\right )} x^{3} + 3 \, {\left (a b^{5} c^{3} - 3 \, a^{2} b^{4} c^{2} d + 3 \, a^{3} b^{3} c d^{2} - a^{4} b^{2} d^{3}\right )} x^{2} + 3 \, {\left (a^{2} b^{4} c^{3} - 3 \, a^{3} b^{3} c^{2} d + 3 \, a^{4} b^{2} c d^{2} - a^{5} b d^{3}\right )} x\right )}} \]
[In]
[Out]
Timed out. \[ \int \frac {1}{(a+b x)^{15/4} \sqrt [4]{c+d x}} \, dx=\text {Timed out} \]
[In]
[Out]
\[ \int \frac {1}{(a+b x)^{15/4} \sqrt [4]{c+d x}} \, dx=\int { \frac {1}{{\left (b x + a\right )}^{\frac {15}{4}} {\left (d x + c\right )}^{\frac {1}{4}}} \,d x } \]
[In]
[Out]
\[ \int \frac {1}{(a+b x)^{15/4} \sqrt [4]{c+d x}} \, dx=\int { \frac {1}{{\left (b x + a\right )}^{\frac {15}{4}} {\left (d x + c\right )}^{\frac {1}{4}}} \,d x } \]
[In]
[Out]
Timed out. \[ \int \frac {1}{(a+b x)^{15/4} \sqrt [4]{c+d x}} \, dx=\int \frac {1}{{\left (a+b\,x\right )}^{15/4}\,{\left (c+d\,x\right )}^{1/4}} \,d x \]
[In]
[Out]